Question

14. If x/2 = y/3 = z/7, then the value of (2x–5y+4z)/2y is
(a) 6/23
(b) 23/6
(c) 3/2
(d) 17/6​

Answer 1

Answer:

x/2=y/3=z/7

y=x/2×3

=3x/2

z = x/2×7

=7x/2

(2x-5y+4z)/2

={2x - (5× 3x/2) +4×7x/2}/2

={2x- 15x/2 +14x} /2

={4x -15x +28x/2}/2

=17x/2× 1/2

=17/4

Answer 2

Answer:

d ( 17/6)

Step-by-step explanation:

Let us assume that x/2 = y/3 = z/7=k

so we will be having x=2k, y=3k , z=7k

Now just put the value of x,y and z

we will get as :

2. 2k - 5. 3k + 4. 7k / 2 . 3k

4k - 15k + 28k/ 6k

17/6

Hope it was easy way.