Question

14. If x = V3 + V2/ V3 - V2 then find the value of x sqare?
​

Answer 1

$x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ x = \frac{3 + 2 + 2 \sqrt{6} }{3 - 2} \\ x = 5 + 2 \sqrt{6} \\ {x}^{2} = ( {5 + 2 \sqrt{6} })^{2} \\ {x}^{2} = 25 + 24 + 20 \sqrt{6} \\ {x}^{2} = 49 + 20 \sqrt{6}$