Question

14. If x + y = 12 and xy = 14, find the value of (x2+y
2​

Answer 1

Step-by-step explanation:

(x+y)²=x²+y²+2xy

(12)²= x²+y²+2(14)

144=x²+y²+28

x²+y²= 144-28

x²+y²= 116

Answer 2

Step-by-step explanation:

x+y=12

XY=14then find x²+y²

x²+y² =(x+y)²-2xy

( 12)²-2*14

144-28

116