Question

14. If x + y = 12 and xy = 14, find the value of (x2 + y²).
please give the answer in step by step but don't send irrelevant answers please ​

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

x+y = 12

xy = 14

y(x+y = 12)

xy = 14

xy+y^2 = 12y

xy = 14  

xy = 12y-y^2

xy = 15

Therefore,

12y-y^2 = 15

$-y^{2}$+12y-15 = 0

= $\sqrt{3 (4y-5)}$ or $-\sqrt{3(4y-5)}$