14. In a triangle ABC, AB = 6, BC = 8 and
AC = 10. A perpendicular dropped from B.
meets in side AC at D. A circle of radius
BD (with center B) is drawn. If the circle
cuts AB and BC at P and Q, respectively,
then AP:QC is equal to:
(a) 1:1
(b) 3:2
(c) 4:1
(d) 3:8
Answers
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Answer:
Option D,
3:8
Step-by-step explanation:
Area of Triangle ABC = 1/2 x 6 x 8 = 24 sq.units
Area of triangle ABD = 1/2 x 10 x BD = 24
BD = 4.8
AP= 6 - 4.8 = 1.2
QC = 8 - 4.8 =3.2
AP/QC = 1.2/3.2 = 3/8
answer: 3:8
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