Question

14.In an equilateral triangle ABC,AD is the altitude from A on BC, then
ЗАВ? =
[a] 2 AD?
[b] 4AD2
O Option
Option 2
[c] 5AD
[d] 6AD2​

Answer 1

ANSWER:

[b] 4AD^2

EXPLAINATION:

Given, ABC is a equilateral triangle

So, AB=BC=CA=a (let)

In ΔABD and ΔACD

AB=AC and AD=AD

∠ADB=∠ADC

∴ΔABD≅ΔACD

Thus BD=CD= a/2

Now in ΔABD∠D=90

⇒AB^2= BD^2+AD^2 = [ CD/2 ] ^2 = AD^2

⇒3AB=4AD^2

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