14. In Fig. 9.13, anglwABD = 110° and angle BAC = 50°. Determine angle BCA.
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Answered by
6
let angle BCA be x
Angle ABD = Angle BAC + Angle BCA
110=50 + x
110-50=x
x= 60
Therefore, Angle BCA = 60 degrees
Answered by
4
Step-by-step explanation:
Sol. ∵ Ext. ∠ of a ∆ is equal to the sum of the two interior opp. ∠s
∴ ∠ABC = ∠BAC + ∠BCA
=> 110° = 50° + ∠BAC
=> ∠BAC = 110° - 50°
=> ∠BAC = 60°
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