Question

14. In Fig. 9.13, anglwABD = 110° and angle BAC = 50°. Determine angle BCA.​

Answer 1

let angle BCA be x

Angle ABD = Angle BAC + Angle BCA

110=50 + x

110-50=x

x= 60

Therefore, Angle BCA = 60 degrees

Answer 2

Step-by-step explanation:

Sol. ∵ Ext. ∠ of a ∆ is equal to the sum of the two interior opp. ∠s

∴ ∠ABC = ∠BAC + ∠BCA

=> 110° = 50° + ∠BAC

=> ∠BAC = 110° - 50°

=> ∠BAC = 60°