Question

14. In fig, AB = EF, BC = ED. AB 1 BD,FE I EC, prove that AABD = AFEC.
F
+
I
B В
C
D​

Answer 1

Answer:

answer

Step-by-step explanation:

AB =EF

BC =ED

BC + CD= ED+CD

BD =CE

ANGLE ABD= ANGLE FEC

HENCE LHS = TO RHS

HENCE VERIFIED BY RHS CONGRUENT RULE