Question

14. In how many different ways the letters of the word ALGEBRA can be arranged in a row if
(i) the two A's are together?
(ii) the two A's are not together?​

Answer 1

Sol: In a word ALGEBRA have 2 A's and 5 different letters are there.

1) Two A's will take 1 unit and 5 letters will take 5 units then total number units = 6.

These can be arranged in 6! = 6x5x4x3x2x1 = 720 ways.

2) The number of arrangements in which two A's together is = 720 ways.

The number of arrangements with out any restriction = 7! / 2! = 2520 ways.

The required number of arrangements if two A's are not together = 2520 - 720 = 1800 ways.

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Answer 2

Answer:

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