Question

14. In the fig, AABC and AABD are such that AD = BC, L1= 22 and 23= 24. Prove that BD = AC.​

Answer 1

In ∆ABC and ∆ABD,

Proof :-

<1 = <2 (given)

<3 = <4 (given)

AD = BC (given)

∆ABC $\cong$ ∆ABD (AAS)

BD = AC {C.P.C.T}

Answer 2

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