14.In the figure O is the centre of a circle. If ∠OAC=50 then ∠ODB=?
1 point
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(a) 40
(b) 50
(c) 60
(d)75
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Step-by-step explanation:
In the figure,
OA = OC = OD = OB ( all are radius of circle of center o)
Now,
angle CAO = angle OBD = 50° ( alternate angles)
Now,
In triangle OBD
angle OBD = 50°
OD = OB ( radii of same circle )
Therefore,
angle ODB = 50°
because opposite angle of equal sides are equal
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