Question

14) In the following diagram, ABCD is a quadrilateral in which, BC=CD ∠CDA=75ᵒ∠ABC=120ᵒ, ∠BCD=110ᵒ. Point X is on AD is such that BX//CD. Find ∠BXA, ∠BDX and ∠BXD giving reasons.

Answer 1

Step-by-step explanation:

In BCD,

∠BDC + ∠BCD + ∠CBD = 180°[

Sum of angles of triangle]

∠BDC + 30° + 30° = 180°

∠BDC + 60° = 180°

∠BDC = 120 - 60= 60

Angle BAC = 60

Answer 2

Answer:

In triangle BCD,

<BCD+<BDC+<DBC=180°

or, <BCD+30°+30°=180°

or, <BCD+60°=180°

or, <BCD=180°-60°

So, <BCD=120°

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