Question

14. In the given figure, points A and B are on the opposite edges of a pond. To find the distance between the two points A and B, the surveyor makes a right-angled triangle. Find the distance AB, if AD = 50m, DC = 120m and BC = 40m. A B. 40 m с 50 m 120 m D​

Answer 1

Answer:

Hence y=2. Thus the side of the triangle is x+y−1=6+2−1=7cm. Its perimeter is 3×7=21 cm.

Answer 2

Answer:

Here, ADC is a right-angled triangle.

⇒(AC)

2

=(30)

2

+(40)

2

⇒(AC)

2

=900+1600

⇒(AC)

2

=2500

⇒AC=

2500

⇒AC=50m

Now,

⇒AB=AC−BC

⇒AB=50−12

⇒AB=38

Therefore, 38m is the distance of AB

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