Question

14. Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.​

Answer 1

Solution :-

Let’s assume $\: A_1, A_2, A_3, A_4, and \: A_5$to be five numbers between 8 and 26 such that 8, $A_1, A_2, A_3, A_4, A_5,$26 are in an A.P.

↪Here we have,

↪a = 8, b = 26, n = 7

So,

↪26 = 8 + (7 – 1) d

↪6d = 26 – 8 = 18

↪d = 3.

Now,

↪$A_{1}$ = a + d = 8 + 3 = 11

↪$A_{2}$= a + 2d = 8 + 2 × 3 = 8 + 6 = 14

↪$A_{3}$= a + 3d = 8 + 3 × 3 = 8 + 9 = 17

↪$A_{4}$ = a + 4d = 8 + 4 × 3 = 8 + 12 = 20

↪$A_{5}$ = a + 5d = 8 + 5 × 3 = 8 + 15 = 23

Therefore, the required five numbers between 8 and 26 are 11, 14, 17, 20, and 23.

Answer 2

Answer:

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