Math, asked by shyamalacbt39, 9 months ago

14. Kamala borrowed from Ratan a certain sum at a certain rate for two years since
At the end of two years she received Rs 210 as compound interest, but paid Rs 20
interest. She lent this sum at the same rate to Hari for two years compound interest
being compounded half-yearly?
only as simple interest. Find the sum and the rate of interest.
nt to Rs 2315 25 in an years​

Answers

Answered by ajhaymadan
1

Answer:

hi...here is your answer

Step-by-step explanation:

Given,

C.I that Kamla receive = Rs.210

S.I that Kamla paid = Rs.200

Time = 2 years

So,

S.I =  

Also,  

C.I. = Total amount - Principal amount  

C.I =  

210 =  

we know,  

(a + b)2 = a2 + b2 + 2ab

R = 10%

From equation (i)

P × R = 10000

Answered by sriramnaveen797
0

Answer:

Step-by-step explanation:

Given details are,

C.I that Kamala receives = Rs 210

S.I that Kamala paid = Rs 200

Time = 2 years

So,

We know, SI = PTR/100

= P×2×R/100

P×R = 10000 ………….. Equation 1

CI = A – P

CI = P [(1 + R/100)n – 1]

210 = P [(1 + R/100)2 – 1]

210 = P (12 + R2/1002 + 2(1)(R/100) – 1) (by using the formula (a+b)2)

210 = P (1 + R2/10000 + R/50 – 1)

210 = P (R2/10000 + R/50)

210 = PR2/10000 + PR/50

We know PR = 10000 from Equation 1

210 = 10000R/10000 + 10000/50

210 = R + 200

R = 210 – 200

= 10%

In Equation 1, PR = 10000

P = 10000/R

= 10000/10

= 1000

∴ Required sum is Rs 1000

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