Question

14) Let a,ß be the roots of the equation ( x - a)(x - b) = C, C+0, then he
roots of the equation ( x - a)(x-B) + c = 0 are
a) a,c
b) b c
c)a, b
d) a + c, b + c​

Answer 1

Answer:

Given α,β are the roots of (x−a)(x−b)−c=0

⇒(x−a)(x−b)−c=(x−α)(x−β)

⇒(x−a)(x−b)=(x−α)(x−β)+c

⇒a,b are the roots of equation (x−α)(x−β)+c=0