14 litre of a diluted acid were put in the two jars the ratio of acid and water the first and in the second jar being 7:2 and 2:1 respectively. They were mixed and put in a single jar, if the ratio of acid and water in the newly formed mixture be 5:2, fine how many liters of liquid in the first jar.
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Answer:
Let the quantity of mixture in each container be x. Then,
Sulphuric acid in 1 st container =
5
3x
Water in 1 st container =
5
2x
Sulphuric acid in 2 nd container =
10
7x
Water is 2nd container =
10
3x
Sulphuric acid in 3rd container =
15
11x
Water in 3rd container =
15
4x
∴ Required ratio =(
5
3x
+
10
7x
+
15
11x
):(
5
2x
+
10
3x
+
15
4x
)=(
60
36+42+44
):(
60
24+18+16
)=122:58=61:29.
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