Question

14 ml of alcohol is present in 42 ml of water find the concentration of solution​

Answer 1

volume of solution = 14 ml + 42 ml = 56 ml

Volume Percent=Volume of Solute ÷ Volume of Solution×100%

V% =

$\frac{14}{56} \times 100$

=

$\frac{1}{4} \times 100$

= 25%