Question

14. One of the two numbers exceeds the other by 9. Four times the smaller added to five times the larger gives 108. Find the numbers.​

Answer 1

Answer:

let the no.s be x and (x+9)

then AtQ

4x+5 (x+9)=108

so 4x+5x+45= 108

so 9x =108 - 45

so 9x= 63

so x= 63/9=7

therefore the the no.s are 7 and 16.

I hope it will help you.