14. P and Q invest 36,000 and 25,000 respectively at the same rate of interest per
year. If at the end of 4 years, P gets 3,080 more interest than Q, find the rate of
interest
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P’s investment (p1) = Rs. 36000
And Q’S Investment (p2) = Rs. 25000
Period (T) = 4 years, Let rate of interest = x %
Q’s interest = Rs. (36000 × x × 4)/100
= Rs. 1440x (∵ S.I. = PRT/100)
And Q’s interest = 25000 × x × 4/100 = Rs. 1000x
Difference in their interest
= Rs. (1440 – 1000)x = Rs. 440x
But difference = Rs. 3080
∴ 440x = 3080 ⇒ x = 3080/440 ⇒ x = 7%
∴ Rate of interest = 7% p.a.
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0
Answer is 7%
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