14. P and Q invest 36,000 and 25,000 respectively at the same rate of interest per year. If at the end of 4 years, P gets 3,080 more interest than Q, find the rate of interest.
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Question:-
P and Q invest 36,000 and 25,000 respectively at the same rate of interest per year. If at the end of 4 years, P gets 3,080 more interest than Q, find the rate of interest.
Required Answer:-
Given:-
- P and Q invest 36,000 and 25,000 respectively at a same rate of interest. per year.
- At the end of 4 years, P gets 3,080 more interest than Q
To Find:-
- The rate of the interest.
Solution:-
Let,
- → P's invest p = Rs. 36000
- → Q's invest p' = Rs. 25000
- → Rate of the interest = R%
- → Time T = 4 years.
We know that:-
- I = PTR
Where,
- I = Simple Interest
- P = Principle Amount
- T = Time
- R = Rate of interest
Therefore,
☆P's interest = p x T x R%
- P's interest = Rs. (36000 x 4 x R)/100
- P's interest = Rs. 144000R/100
- P's interest = Rs. 1440R
Again,
☆Q's interest = p' x T x R%
- Q's interest = Rs. (25000 x 4 x R)/100
- Q's interest = Rs. 100000R/100
- Q's interest = Rs. 1000R
Difference in P's and Q's interest:-
☆P's interest - Q's Interest = Rs. (1440R - 1000R) = Rs. 440R
According to the Question:-
440R = 3080
- ⇒ R = (3080/440)%
- ⇒ R = 7%
★ Hence, rate of the interest is 7%
Some Important Informations:-
- Simple Interest:- Simple interest is a quick and easy method of calculating the interest charge on a loan.
- Compound Interest:- Compound interest is the interest on a loan or deposit calculated based on both the initial principal and the accumulated interest from previous periods.
- Simple Interest Formula:- I = PTR
- Compound Interest Formula:- C = A - P
- Final Amount Formula (During simple interest):- A = P(1 + TR)
- Final Amount Formula (During compound interest):- A = P(1 + R)^T
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