Question

14) Prove that 7 + 3 root
2 is an irrational number.​

Answer 1

Step-by-step explanation:

7

7 +  3 \sqrt{2 }  = p \div q \\ 3 \sqrt{2}   =  \frac{p - 7q}{q}  \\  \sqrt{2}  =  \frac{p - 7q}{3q}  

p-7q and 3q are integrr but our contradiction is wrong so 7+3root2 is irrational  

(BEFORE WE START OUR SOLUTION PLZ LET THE NO. RATIONAL BY CONTRADICTION )

Answer 2

Answer:

7+3√2,these are rational no.

Step-by-step explanation:

7+3√2=a/b

=3√2=a/b-7

=a-7b/b

=√2=a-7b/5b

=

so,7+3√2is also an irrational no..

thanks