Question

14. Prove that:
(a) (x + y)(x - y) + (y +z)(y - z) + (z + x)(z - x) = 0​

Answer 1

Answer:

(x + y)(x - y) + (y +z)(y - z) + (z + x)(z - x) = 0__(given)

Solⁿ:– (x²-xy+yx-y²)+(y²-yz+zy-z²)+(z²-zx+xz-x²) = 0

x²-x² -y²+y²-z²+z²-xy+yx-yz+zy-zx+xz = 0

0 = 0

Hence Proved !

Answer 2

Answer:

Solve to your problem....