14. Prove that cos(A + B) cos C - cos(B+C) cos A = sin B sin(C - A)
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cos(A+B)cosC - cos(B+C)cosA
= (cosAcosB - sinAsinB)cosC - (cosBcosC - sinBsinC)cosA
= cosAcosBcosC - sinAsinBcosC - cosAcosBcosC + sinBsinCcosA
= sinB ( sinCcosA - sinAcosA )
= sinB sin(C-A)
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