Question

14. Simplest rationalisation factor of cube√40 is​

Answer 1

Answer:

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

Explanation:

$\sqrt[3]{40} = \sqrt[3]{8 \times 5} \\ \\ \sqrt[3]{8 \times 5} = \sqrt[3]{8} \times \sqrt[3]{5} \\ \\ \sqrt[3]{8} \times \sqrt[3]{5} = 2 \times \sqrt[3]{5} = 2 \sqrt[3]{5}$