Math, asked by SwarnadipDas, 8 months ago


14. () (sin x + cos x) (sec x + cosec x) = 2 + sec x cosec x​

Answers

Answered by Abhilash210
2

Step-by-step explanation:

LHS= (sinx+cosx)(secx+cosecx)

=(sinx+cosx)(1/cosx+1/sinx)

=(sinx+cosx){(sinx+cosx)/sinx cosx}

=(sinx+cosx)²/sinxcosx

=(sin²x+cos²x+2sinxcosx)/sinxcosx

=2sinxcosx/sinxcosx + sin²xcos²x /

sinxcosx

= 2 + 1/sinxcosx

= 2 + secx cosecx

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