Question

14. subtrait
(a-b+c)-2(a+b-c) from 5 (a+2b-c )​

Answer 1

✧$\huge \mathcal \red {\underline{\underline{A}}}$ $\huge \mathcal \green {\underline{\underline{N}}}$ $\huge \mathcal \pink {\underline{\underline{S}}}$ $\huge \mathcal \blue {\underline{\underline{W}}}$ $\huge \mathcal \orange {\underline{\underline {E}}}$ $\huge \mathcal \purple {\underline{\underline{R}}}$✧

Given :

Subtract

$(a - b + c) - 2 (a + b - c) from 5 (a + 2b - c)$

To find :

The resultant value by subtraction

Solution :

$(a - b + c) - 2 (a + b - c) from 5 (a + 2b - c)$

➜ $[5 (a + 2b - c)] - [(a - b + c) - 2 (a + b- c)]$

➜ $[5a + 10b - 5c] - [a - b + c - 2a - 2b + 2c]$

➜ $[5a + 10b - 5c] - [-a - 3b + 3c]$

➜ $5a + 10b - 5c + a + 3b - 3c$

➜ $6a + 13b - 8c$

Results :

$\implies \texttt {Hence, the answer is 6a + 13b - 8c.}$

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