Math, asked by shironiakshayac, 7 months ago

14. Sum of n terms of the A.P. 73, 112, 127, 148
is
13
ull
(1) n(n-1)
(2) n (n + 1)2
2.
2
(3) n(n+1) 13
(4) 73 n(n-1)​

Answers

Answered by gauri3077
0

Answer:

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Answered by MausamMagar
1

Answer:

Sum of n terms of the A.P. 73, 112, 127, 148  is  13

the question is not clear yet,

A.P. 73, 112, 127, 148  is  13

a1 =73, a2= 112, a3 = 127 and a4 = 148

d1= a2-a1

d1= 112-73

d1= 39

again,

d2=a3-a2

d2= 127-112

d2=15

here d1 is not equal to d2

the series is not an AP

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