Question

14. Sum of the digits of a two – digit number is 11. If the number obtained by reversing the digits is 9 less than the original number find the orginal number

Answer 1

Answer:

65

Step-by-step explanation:

Given,

Sum of digits of two digit number = 11

Let, the digits of two digit number be 'x' and 'y'.

So, the number = 10x + y

Sum of its digits = 11

x + y = 11

x = 11 - y ---------- equation 1

According to the problem,

10y + x = (10x + y) - 9

10y + x - 10x - y = - 9

9y - 9x = -9

y - x = -1 ---------- equation 2

Substitute equation 1 in 2

y - 11 + y = -1

2y = 10

y = 5

Substitute y = 5 in equation 1

x = 11 - 5

x = 6

Number = 10x + y

= 10(6) + 5

= 65

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