Math, asked by noornoor51183, 3 months ago

14.
Take a 3 digit number 109 use this number to form 2 more 3 digit numbers such that no visit is repeated at the same place value twice. Add them up divide the answer by 37. Is there any remainder?​

Answers

Answered by KushalTomar2008
0

Answer:

Step-by-step explanation:

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Answered by Swarup1998
1

Step-by-step explanation:

  • STEP 1. The given number is 109. The digits are 1, 0 and 9. The three digit numbers that we can form using 1, 0, 9 are 190, 901 and 910.

The given condition states that we have to take those two numbers whose places are not repeated with same digit.

  • STEP 2. The numbers that we can take as a pair are (190, 901), (190, 910) and (901, 910). Of these, the only pair that fulfills the given condition of no-repeats is (190, 901).

  • STEP 3. Finding the sum of 190 and 901: 190 + 901 = 1091.

STEP 4. Let us divide 1091 by 37 now and check for any remainder.

37 ) 1091 ( 29

- 74

____

351

- 333

____

18

We get remainder = 18.

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