Question

14. Test the divisibility of:
(i) 10000001 by 11
(iv) 1000 1001 by 3
(ii) 19083625 by 11
(v) 10203574 by 4
(iii) 2134563 by 9
(vi) 12030624 by 8



Pls Step - By - Step Solutions ​

Answer 1

Answer:

1) 10000001 by 11

1+0+0+0=1

1+0+0+0=1

=>1-1=0

:. 10000001 is divisible by 11 as after subtracting odd places no. from even places no. we got zero

4) 10001001 by 3

1+0+0+0+1+0+0+1=3

:.10001001 is divisible by 3 as after adding the every digit numbers we got 3 which is divisible by 3

2)19083625 by 11

odd places no.= 5+6+8+9=28------1

even places no.=2+3+0+1=6-------2

subtracting 2 from 1

=>28-6=22

:.the given no.is divisible by 11 as 22 is divisible by 11

5)10203574 by 4

the given no. is not divisible by 4 because the last two digits i.e 74 is not divisible by 4

3) 2134563 by 9

2+1+3+4+5+6+3=24

the given no. is not divisible by 9 as the number obtained(24) is not a multiple of 9

6) 12030624 by 8

the given no.is divisible by 8 as the last three digit I.e 624 is divisible by 8

hope it helps