14. The age of a father 8 years back was 5 times that of his son.
After 8 years, his age will be 8 years more than double the age of his
son. Find their present ages.
Answers
Answer:
Let the present age of father and his son be X and Y year's.
Before 8 years age of father = (X-8) years
Before 8 years age of son = (Y-8) years
According to question,
(X-8) = 5(Y-8)
X - 8 = 5Y - 40
X - 5Y = -40 + 8
X - 5Y = -32------------(1)
After 8 years age of father = (X+8) years
After 8 years age of son = (Y+8) years
According to question,
(X+8) = 2(Y+8) + 8
X + 8 = 2Y + 16 +8
X + 8 = 2Y + 24
X - 2Y = 24 -8
X - 2Y = 16--------(2)
From equation (1) we get,
X - 5Y = -32
X = -32 + 5Y----------(3)
Putting the value of X in equation (2)
X - 2Y = 16
-32 + 5Y - 2Y = 16
3Y = 16 + 32
3Y = 48
Y = 48/3
Y = 16 years
Putting the value of Y in equation (3)
X = -32+5Y => -32 + 5 × 16 => -32 + 80
X = 48 years
Age of father = X = 48 years
And,
Age of son = Y = 16 years
HOPE IT WILL HELP YOU....... :-)
Step-by-step explanation:
Answer:
Step-by-step explanation:Hiiii friend,
Let the present age of father and his son be X and Y year's.
Before 8 years age of father = (X-8) years
Before 8 years age of son = (Y-8) years
According to question,
(X-8) = 5(Y-8)
X - 8 = 5Y - 40
According to question,
(X-8) = 5(Y-8)
X - 8 = 5Y - 40
X - 5Y = -40 + 8
X - 5Y = -32------------(1)
After 8 years age of father = (X+8) years
After 8 years age of son = (Y+8) years
According to question,X+8) = 2(Y+8) + 8
X + 8 = 2Y + 16 +8
X + 8 = 2Y + 24
X - 2Y = 24 -8
X - 2Y = 16--------(2)
From equation (1) we get,
X - 5Y = -32
X = -32 + 5Y----------(3)
Putting the value of X in equation (2)X - 2Y = 16
-32 + 5Y - 2Y = 16
3Y = 16 + 32
3Y = 48
Y = 48/3
Y = 16 years
Putting the value of Y in equation (3)
X = -32+5Y => -32 + 5 × 16 => -32 + 80
X = 48 years
R