Question

14. The angle of projection of a projectile which is
projected with certain velocity from ground is π/8 with
horizontal and its horizontal range is R. The angle
with the horizontal for another projectile having same
range R and speed is
[NCERT Pg. 78]
370
(1)3π/8
(2) π/4
(3) π/3
(4) π/6
please give a solved answer​

Answer 1

Answer:

If angle is ß and 90 - ß and have same speed then both projectile has same range.

Here ß = π/8

So 90 - ß = π/2 -π/8 = 3π/8

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