Question

14
The angles of a triangle are in the ratio 2:3:5. Find the largest angle.​

Answer 1

Step-by-step explanation:

Let the common multiplier of the given ratios be x.

Therefore measures of given angles will be 2x, 3x and 5x

Now, by angle sum property of a triangle, we have:

2x + 3x + 5x = 180°

$\implies \: 10x = 180 \degree \\ \implies \: x = \frac{180\degree}{10} \\ \implies \: x = 18 \degree \\ \therefore \: 2x = 2 \times 18 = 36 \degree \\ \: \: \: \: \: 3x = 3 \times 18 = 54 \degree \\ \: \: \: \: \: 5x = 5\times 18 = 90 \degree \\ thus \: the \: largest \: \angle \: of \: the \: \triangle \: is \: \\ 90 \degree.$

Answer 2

Answer:90

Step-by-step explanation:

2u+3u+5u=180

10u=180

u=18

Largest is 5u which is equal to 5*18

90