Question

14. The area of AABC is A 3cm B 4cm el 03 sq.cm 3 04 sq.cm 6 sq.cm O 12 sg.cm ​

Answer 1

Given, In a ∆ABC

Height = AB = 3cm

Base = BC = 4cm

find the Area of the ∆ABC

Solution :

Let's solve this by using,

$\underline{ \boxed{ \color{gold} \bf Area = \frac{1}{2} \times base \times height}}$

on substituting the values,

$\rm Area = \frac{1}{ \cancel2} \times \cancel4 \times 3$

$\boxed{ \color{orange} \bf Area = 6sq.cm}$

FINAL ANSWER :

Area of the ∆ABC is 6cm² .

Answer 2

Answer:

$given = abc$is a triangle

$bc \: is \: the \: base \: so \: it \: is \: the \: length \: of \: 4cm</p><p>[tex]</p><p>[tex]ab \: is \: the \: height \:$

$length = 3cm$

$area \: of \: triangle = \frac{1}{2} \times base \: \times height$

$or \: it \: can \: be \: written \: as \: \frac{1}{2} bh$

$on \: substituting \: the \: values \: we \: get$

$= \frac{1}{2} \times 4cm \times 3cm$

$= \frac{1}{2} \times 12cm^{2}$

$= 6cm^{2} or \: 6sq.cm$

therefore area of ∆ABC IS 6sq.cm

Step-by-step explanation:

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