Question

14. The area of the triangle formed by joining the origin to the points of intersection of the line
XV5+2y = 3/5 and the circle x2 + y2 = 10 is​

Answer 1

Answer:

Length of perpendicular from origin to the line x

5

+2y=3

5

is

OL=

(

5

)

2

+2

2

3

5

=

9

3

5

=

5

Radius of the given circle =

10

=OQ=OP

PQ=2QL=2

QL

2

−OL

2

=2

10−5

=2

5

Thus, area of△OPQ=

2

1

×PQ×OL

area of△OPQ=

2

1

×2

5

×

5

=5 sq.units

solution

Step-by-step explanation:

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