Question

14. The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is [2005] M mm
(a) Zero
(b) ML2 /k
(c)
$\sqrt{mkl}$
d) kl2 /2m

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Answer 1

Answer:

Option c

Explanation:

The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is [2005] M mm

C)

Answer 2

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