14) The diameter of a sphere is decreased by 25%. By what percent does its S.A
decrease?
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Answer:
GIVEN- ATQ-Original Diameter =d
GENERALLY-Original CSA=4π(2d)2=πd2
AFTER EDITING-New Diameter =d−10025d=43d
SO,New CSA=4π(83d)2=169πd2.
% decrease =πd2(πd2−169πd2)×100
NOW , =πd2πd2(1−169)×100
=1616−9×100
=43.75% HOPE IT HELPS: ).
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