Question

14) The diameter of a sphere is decreased by 25%. By what percent does its S.A

decrease?​

Answer 1

Answer:

GIVEN- ATQ-Original Diameter =d

GENERALLY-Original CSA=4π(2d)2=πd2

AFTER EDITING-New Diameter =d−10025d=43d

SO,New CSA=4π(83d)2=169πd2.

% decrease =πd2(πd2−169πd2)×100

NOW , =πd2πd2(1−169)×100

=1616−9×100

=43.75% HOPE IT HELPS: ).

Step-by-step explanation:

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