14. The dimension of 1/2eta E^2 where ε, is permittivity of
free space and E is electric field, is
[AIPMT (Prelims)-2010]
(1) ML2T-2
(2) ML-1 T-2
(3) ML2T-1
(4) MLT-1
Answers
Answered by
1
Answer:
dimensionsof
2
1
ε
0
E
2
[E]=MLT
−2
Q
−1
[ε
0
]=[M
−1
L
−3
T
2
Q
2
]
ε
0
E
2
=[M
−1
L
−3
T
2
Q
2
]×[MLT
−2
Q
−1
]
2
=M
−1+2
L
−3+2
T
2−4
Q
2−2
=ML
−1
T
−2
Explanation:
plz make me as brainlist
Similar questions