Question

14.The exterior angle of a triangle is 108 and the interior opposite
angles are in ratio 4:5 . the angles of the triangle are.







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Answer 1

Answer:

The exterior angle of a triangle =108

let the opposite angles are 4x and 5x respectively

4x+ 5x =108

9x = 108

9x =108

x = 12

therefore, 4(12) =48

5(12)= 60

so, A+B+C =180

48+60+C=180

108+ C =180

C = 180-108

C = 72

Step-by-step explanation:

Answer 2

Answer:

GIVEN THAT THE EXTERIOR ANGLE OF TRIANGLE IS 108.....

INTERIOR ANGLE OF GIVEN TRIANGLE ARE IN THE RATIO OF 4:5

WE KNOW THAT.....

SUM OF 2 INTERIOR ANGLES IN TRIANGLE IS 1 EXTERIOR ANGLE

4X+5X=108

9X=108

X=108/9

X=12

HERE X=12

SO...

4X=4×12=48(FIRST ANGLE)

5X=5×12=60(SECOND ANGLE)

SUM OF ANGLES IN TRIANGLE IS 180°

48°+60°+X=180°

108°+X=180°

X=180°-108°

X=72°(THIRD ANGLE)

THEREFORE THE ANGLES IN TRIANGLE ARE 48°, 60°, 72°