Question

14. The father's age is six times points
of his son's age. Four years
hence, the age of the father
will be four times of his son's
age.
The present ages, in
years, of the son and the
father are, respectively.​

Answer 1

Answer:

6 and 36 respectively

Step-by-step explanation:

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ......... (1)

x+4=4(y+4) ..... (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

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Answer 2

Answer:

Present age of father is 36 years and present age of his son is 6 years.

Step-by-step explanation:

Let the present age of father be x years and the present age of son be y years. Therefore, the present age of father is 36 years and the present age of his son is 6 years.