Question

14. The first terms of an AP, whose first term is - 2 and the common difference is - 2 are​

Answer 1

a = -2. and. d = -2

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$\implies a + (n - 1)d. \\ \\ \implies - 2 + (n - 1) - 2. \\ \\ \implies -\cancel 2 - 2n + \cancel2. \\ \\ \implies - 2n. \\ \\ \implies - n = \frac{0}{2} \\ \\ \implies \: n = 0$

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Answer 2

Answer:

-4,-6,-8,-10,......

Step-by-step explanation:

formula:

a(n-1)d

n=nth term

a=first term

d=common difference

a(n-1)d

-2(2-1)-2

-2(1)-2

-4

a(n-1)d

-2(3-1)-2

-2(2)-2

-2-4

-6

and continue this process