Question

14. The
least multiple of 13, which on dividing
by 4, 5, 6, 7 & 8
leaves
remainder 2 in each case.
2
is - ?
The
no,​

Answer 1

Answer:

lets find out the LCM of 4, 5, 6, 7 and 8 = 840.

Step-by-step explanation:

Let required number be 840 K + 2 which is multiple of 13.

Least value of K for which ( 840 K + 2 ) is divisible by 13 is K = 3

∴ Required number = 840 × 3 + 2

Required number = 2520 + 2 = 2522

hope it helps!!