Question

14. The length of a rectangle is 8cm more than the breadth. If the perimeter of rectangle la 56 cm



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Answer 1

$\pink{\bold{\underline{\underline{Answer:}}}}$

$\mathcal\green{Let\:length\:be\:x\:then\:breadth\:be \: x\:+\:8}$

$\mathcal{A\Q}$

$\purple{Perimeter}$ = $\pink{2(l+b)}$

${56\:cm}$ = ${2(x+x+8)}$

${2(2x+8)}$ =${56\:cm}$

${4x+16}$ =${56\:cm}$

${4x}$ = ${56+16}$

${x}$ = $\frac{72}{4}$

${x}$ = ${18}$

$\mathcal\red{Length}$ = ${18}$

$\mathcal\pink{Breadth}$ = ${26}$