Question

14. The lengths of the sides of a triangle are 33 cm, 44 cm and 55 cm respectively. Find the area
of the triangle and hence find the height corresponding to the side measuring 44 cm
​

Answer 1

Answer:

=33cm

Step-by-step explanation:

(couldn't think of anything else to think of sorryyyyy)

Answer 2

$\huge \sf { \fcolorbox{green}{g}{❃ \: Explanatation \: ❃}}$

$\Large{\underline{\underline{\sf{Given:}}}}$

Side ( a) = 33 cm

side (b) = 44 cm

side (c) = 55cm

Base of triangle = 44cm

$\Large{\underline{\underline{\sf{Find:}}}}$

• Area of triangle

• Heights of triangle

$\Large{\underline{\underline{\sf{Solution:}}}}$

$\: Area \: of \: triangle = \\ \\ \implies \sqrt{s(s- a)(s - b)(s - c) }$

➩ sides (s) = a+b+c/2

Here, s = 33 + 44 + 55 /2

s = 132 /2

s = 66 cm

$\: Area \: of \: triangle = \\ \\ \implies \sqrt{66 \: cm \: (66 - 33)(66 - 44)(66 - 55)} \\ \: \\ \implies \sqrt{66 \: cm \: \times 33 \: cm \times 22 \: cm\times 11 \: cm} \\ \\ \implies\sqrt{2 \times 3 \times 11 \times 11 \times 3 \times 11 \times 2 \times 11 } \\ \\ \implies \: 11 \times 11 \times 2 \times 3 \\ \\ \: \implies 726 \: cm \: {}^{2}$

Now, Area of triangle= 726 cm ²

Base of triangle = 44 cm ( given )

Therefore, Heights of triangle = Area /base

= 726 cm ²/ 44 cm

= 33cm

Hope it helps you