Question

14. The number of consecutive zeros in 2 raised to power 3 x 3 raised to power 4x 5 raised to power 4x 7, is
(a) 3
(b) 2
(c) 4
(d)5​

Answer 1

Answer:

i think it is 3 (a)

Step-by-step explanation:

hope it hepps you