Question

14. The osmotic pressure (in atm) of 5% solution of glucose (C H202) at 18°C. 1. 8.415 2. 5.231 3. 6.636 4.8.327 ​

Answer 1

Answer:

Let's assume the mass of solution = 100g, and density of water = 1 g/ml

so, mass of glucose =

100

0.5

×100=0.5g

we have,

π=iCRT

since, i=1 for gulucose

π=CRT

π=

180×100

0.5

×1000×291×0.0821

We get,

π=0.6628atm

Hence, option (A) is correct.

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