14. The paint in a certain container is sufficient to paint an area equal to 95.2 m2. How many bricks
of dimensions 22 cm x 10 cm x 8 cm can be painted out of this containe
Answers
Answered by
0
Answer:
area of one brick of the given dimensions/the area that can be painted
so, 2(lb + bh +lh)/95.2 m.sq.
l = 22cm
b= 10 cm
h = 8cm
therefore, 2(22*10 + 10*8 + 8*22)/95.2
which is, 2(220 + 80 + 176)/95.2
= 2*476/95.2
=952/95.2
= 10 bricks
Step-by-step explanation:
area of a cuboid= 2(lb + bh + lh)
Answered by
1
Answer:
Number of bricks = Area to be painted / Area of paint
= 2 (lb+bh+hl)/95.2
= 2 (22 × 10 + 10 × 8 +8 × 22)/95.2
= 2 × (220 + 80 + 176 )/ 95.2
= 2 × 476 / 95.2
= 9420 / 952
= 10 bricks
Hope it helps
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