Math, asked by vivek174451, 11 months ago


14. The paint in a certain container is sufficient to paint an area equal to 95.2 m2. How many bricks
of dimensions 22 cm x 10 cm x 8 cm can be painted out of this containe​

Answers

Answered by kushwahkushagra13
0

Answer:

area of one brick of the given dimensions/the area that can be painted

so, 2(lb + bh +lh)/95.2 m.sq.

l = 22cm

b= 10 cm

h = 8cm

therefore, 2(22*10 + 10*8 + 8*22)/95.2

which is, 2(220 + 80 + 176)/95.2

= 2*476/95.2

=952/95.2

= 10 bricks

Step-by-step explanation:

area of a cuboid= 2(lb + bh + lh)

Answered by YK11728
1

Answer:

Number of bricks = Area to be painted / Area of paint

= 2 (lb+bh+hl)/95.2

= 2 (22 × 10 + 10 × 8 +8 × 22)/95.2

= 2 × (220 + 80 + 176 )/ 95.2

= 2 × 476 / 95.2

= 9420 / 952

= 10 bricks

Hope it helps

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