Question

14. The perimeter of a square field is (4 x +8).
Find the length of its diagonal.
(a) (x + 6)13
(b) (x + 4)/2
(c) (x + 2)2
(d) (x + 5)3​

Answer 1

Answer:

$x \sqrt{2} + 2 \sqrt{2}$

Answer 2

Answer:

We know that ,  

      perimeter of square = 4a

      ⇒  4x + 8 = 4a

      ⇒  a = 4x/4 + 8/4

      ⇒  a = x + 2

We also know that,

      diagonal, d = $\sqrt{2}$ a

       ⇒  d =  $\sqrt{2}$(x + 2)

               Hope it helps you^_^