Question

14. The perimeter of a square field is 4x+8
15 The perimeter of a square and rectangle
are each equal to 48 m and difference
(c) 70 m
7. Let
Find the length of its diagonal.
X
orix+222
So
8. Ac
between area is 4 m². The breadth of the
rectangle is
(b) 12 m
(c) 18 m
(d) 20 m
03 16. Find the number of square tiles of side
12 cm, required for flooring a room of si
#mx 5 m will be
) 1400 (c) 1500
9.
(d) 1601​

Answer 1

Step-by-step explanation:

Answer:-

A cording to Question, only one statement is applicable. The question is :-

Correct Question:-

The perimeter of the square field is 4x+8. Find the area of its diagonal.

Concept:-

Now, here we need to know that:-

$\sf{Area \ of \ Square = a^2}$

$\sf{Perimeter \ of \ Square = 4a}$

Here, a is the side.

So, first, in this question we will find the culprit of the question, which is x.

$\sf{4x + 8 = Perimeter}$

$\sf{4x + 8 = 4a}$

$\sf{a = \dfrac{4(x + 2)}{4}}$

$\sf{a = x + 2}$

Now, we have found the x with respect to a which is the side.

$\sf{Diagonal \ of \ Square = Side \times \sqrt{2}}$

$\sf{Diagonal \ of \ Square = (x+2) \times \sqrt{2}}$

$\sf{Diagonal \ of \ Square = \sqrt{2}x+2 \sqrt{2}}$

So, answer is $\sqrt{2}x+2 \sqrt{2}$.

Answer 2

Question :-

The perimeter of the square field is 4x+8. Find the area of its diagonal.

Required Formulas :-

Perimeter of square = 4a

Area of square = a²

Here ,

" a " = Side of the Square .

Now ,let's find out the value of " x " .

So , According to the Question :-

Perimeter of the Square = 4a

4x + 8 = 4a

4x + 8 / 4 = a

So , therefore taking 4 common , then we get :-

4 ( x + 2 ) /4 = a

4 cancels 4 so we get ( x + 2 ) = a

a = ( x + 2 )